How do you differentiate f(x) = cos (3x -3)?
1 Answer
Jun 5, 2018
Explanation:
Applying chain rule,
Thus...
f'(x)=d/dx(3x-3)*d/dx(\cos(3x-3)) Simplified,
f'(x)=3*(-\sin(3x-3))
=-3\sin(3x-3)