How do you differentiate #f(x)=e^cot(1/sqrt(x)) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Bdub Apr 14, 2016 #f'(x)==e^cot(1/sqrtx)xx-csc^2(1/sqrtx)xx(-1/(2x^(3/2)))# Explanation: #f(x)=e^x, g(x)=cotx, h(x)=1/sqrtx# #f(g(h(x)))=e^cot(1/sqrtx)# #[f(g(h(x)))]'=f'(g(h(x))xxg'(h(x))xxh'(x)# #=e^cot(1/sqrtx)xx-csc^2(1/sqrtx)xx(-1/(2x^(3/2)))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1084 views around the world You can reuse this answer Creative Commons License