How do you differentiate #f(x)= ln(x^2-x)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Guilherme N. Dec 24, 2015 Using chain rule, which states that #(dy)/(dx)=(dy)/(du)(du)/(dx)#, let's rename #u=x^2-x# Explanation: #(df(x))/(dx)=(1/u)(2x-1)# #(df(x))/(dx)=(2x-1)/(x^2-x)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1655 views around the world You can reuse this answer Creative Commons License