Question

How do you differentiate `f(x)=sec(e^(x)-3x )` using the chain rule?

Answer 1

`f'(x)=(e^x-3)sec(e^x-3x)tan(e^x-3x)`

Explanation:

`f(x)=sec(e^x-3x)`

Here outside functions is sec , Derivative of sec(x) is sec(x)tan(x).

#f'(x) =sec(e^x-3x)tan(e^x-3x) derivative of (e^x-3x)

`f'(x) =sec(e^x-3x)tan(e^x-3x) (e^x-3)`

`f'(x)=(e^x-3)sec(e^x-3x)tan(e^x-3x)`