# How do you differentiate f(x)=sqrt(ln((x-2)^2) using the chain rule?

Oct 31, 2016

f(x)=sqrt(ln((x-2)^2)
$f ' \left(x\right) = \left(\frac{1}{2 \sqrt{\ln} \left({\left(x - 2\right)}^{2}\right)}\right) \cdot \frac{1}{x - 2} ^ 2 \cdot 2 \left(x - 2\right) \cdot 1$
$f ' \left(x\right) = \frac{1}{\left(x - 2\right) \sqrt{\ln} \left({\left(x - 2\right)}^{2}\right)}$