Question

How do you differentiate `f(x)=sqrt(ln((x-2)^2)` using the chain rule?

Answer 1

see below

Explanation:

`f(x)=sqrt(ln((x-2)^2)`

`f'(x)=(1/(2sqrtln((x-2)^2))) * 1/(x-2)^2 *2(x-2) *1`

`f'(x)=1/((x-2)sqrtln((x-2)^2))`