Question

How do you differentiate `f(x)=tan(5x^3)`?

Answer 1

`d/dx tan(5x^3)=15x^2sec^2(5x^3)`#

Explanation:

In order to differentiate this function, we need to use the chain rule for `tan(f(x))`:

`d/dxtan(f(x))=sec^2(f(x))xxf'(x)`

`d/dx tan(5x^3)=sec^2(5x^3)15x^2=15x^2sec^2(5x^3)`