How do you differentiate #f(x)=x^4+4^x#?

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Answer 1 · 2017-10-12T16:21:27

Let's see.

For doing this one, you need to know especially two formulas #rarr#

(1). #d/dx(x^n)=nx^(n-1)#.

(2). #d/dx(a^x)=a^xlna#.

Now let the given function be #y#, such that #y=f(x)#.

#:.y=x^4+4^x#

#:.dy/dx=4cdotx^(4-1)+4^xln4#

#:.dy/dx=4x^3+4^xln4#.

Hope it Helps:)