How do you differentiate f(x)=(x-sin3x)^3/9 using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Dr. S Jan 9, 2018 1/3*(1-3cos3x)*(x-sin3x)^2 Explanation: d/dy(((x-sin3x)^3)/9) = d/dy(1/9(x-sin3x)^3) = 1/9*3*(1-cos3x*3)*(x-sin3x)^2 = 1/3*(1-3cos3x)*(x-sin3x)^2 Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 1711 views around the world You can reuse this answer Creative Commons License