# How do you differentiate h(x)=3e^sin(x+2)?

$3 {e}^{\sin} \left(x + 2\right) \cos \left(x + 2\right)$
$\frac{\mathrm{dh}}{\mathrm{dx}} = \frac{d}{\mathrm{dx}} \left(3 {e}^{\sin} \left(x + 2\right)\right) = 3 {e}^{\sin} \left(x + 2\right) \frac{d}{\mathrm{dx}} \left(\sin \left(x + 2\right)\right) =$
$= 3 {e}^{\sin} \left(x + 2\right) \cos \left(x + 2\right) \frac{d}{\mathrm{dx}} \left(x + 2\right) = 3 {e}^{\sin} \left(x + 2\right) \cos \left(x + 2\right)$