# How do you differentiate h(x) = (6x-x^3)^2?

$h ' \left(x\right) = 2 \left(6 x - {x}^{3}\right) \left(6 - 3 {x}^{2}\right) = 6 x \left(6 - {x}^{2}\right) \left(2 - {x}^{2}\right)$