Question

How do you differentiate `ln[(x^4-3x^3+1)^(1/2)]`?

Answer 1

`y'=(4*x^3-9x^2)/(2*(x^4-3x^3+1))`

Explanation:

By the chain and power rule we get

`1/sqrt(x^4-3x^3+1)*1/2*(x^4-3x^3+1)^(-1/2)*(4x^3-9x^2)`

and this is equal to

`(4x^3-9x^2)/(2*(x^4-3x^3+1))`