Question

How do you differentiate `sin^4(x)`?

Answer 1

`dy/dx= 4sin^3xcosx`

Explanation:

Let `y= u^4` and `u = sinx`.

`y' = 4u^3` and `u' = cosx`

`dy/dx= 4u^3 xx cosx = 4(sinx)^3cosx = 4sin^3xcosx`

Hopefully this helps!