How do you differentiate #sin^7(x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Eddie Jun 29, 2016 #= 7 sin ^6 x \ cos x# Explanation: #D(sin^7 x)# by power rule and chain rule #= 7 sin ^6 x * D(sin x)# #= 7 sin ^6 x \ cos x# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2469 views around the world You can reuse this answer Creative Commons License