How do you differentiate sqrt((x+1)/(2x-1))? Calculus Basic Differentiation Rules Chain Rule 1 Answer mizoo Mar 18, 2018 -(3(x+1))/(2(2x-1)^2 sqrt((x+1)/(2x-1)) Explanation: f(x) = u^n f'(x) = n xx (du)/dx xxu^(n-1) In this case: sqrt((x+1)/(2x-1))= ((x+1)/(2x-1))^(1/2): n = 1/2, u = (x+1)/(2x-1) d/dx = 1/2 xx (1xx(2x-1) - 2xx(x+1))/(2x-1)^2 xx ((x+1)/(2x-1))^(1/2-1) = 1/2xx(-3)/((2x-1)^2 xx ((x+1)/(2x-1))^(1/2-1) = -(3(x+1))/(2(2x-1)^2 ((x+1)/(2x-1))^(1/2) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 1691 views around the world You can reuse this answer Creative Commons License