# How do you differentiate the following parametric equation: # x(t)=t^3-5t, y(t)=(t-3) #?

##### 1 Answer

Jan 13, 2016

#### Explanation:

# x = t^3 - 5t rArr dx/dt = 3t^2 - 5 # and

# y = t - 3 rArr dy/dt = 1 #

#dy/dx = dy/dt xx dt/dx # note that:

# dt/dx =( 1)/(dx/dt) #

#rArr dy/dx = 1/(3t^2 - 5 ) #