How do you differentiate x^-7 - 7x^-1? Calculus Basic Differentiation Rules Power Rule 1 Answer David C. Jan 16, 2018 -7x^-8+7x^-2 Explanation: Let y=x^-7-7x^-1 y'=(x^-7)'-(7x^-1)' By the power rule (x^n)'=nx^(n-1) we get: y'=-7x^(-7-1)-7times(-1x^(-1-1)) By simplifying, we get: -7x^-8+7x^-2 Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of y =1/sqrt(x)? How do you find the derivative of y =4/sqrt(x)? How do you find the derivative of y =sqrt(2x)? How do you find the derivative of y =sqrt(3x)? How do you find the derivative of y =sqrt(x)? How do you find the derivative of y =sqrt(x) using the definition of derivative? How do you find the derivative of y =sqrt(3x+1)? How do you find the derivative of y =sqrt(9-x)? How do you find the derivative of y =sqrt(x-1)? See all questions in Power Rule Impact of this question 1797 views around the world You can reuse this answer Creative Commons License