Question

How do you differentiate `x^-7 - 7x^-1`?

Answer 1

`-7x^-8+7x^-2`

Explanation:

Let `y=x^-7-7x^-1`

`y'=(x^-7)'-(7x^-1)'`

By the power rule `(x^n)'=nx^(n-1)` we get:

`y'=-7x^(-7-1)-7times(-1x^(-1-1))`

By simplifying, we get:

`-7x^-8+7x^-2`