How do you differentiate # y = 1/4 [ 1/2ln[x^2 -2x +2/ x^2 + 2x +2] + tan^-1[2x/2-x^2]]#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Frederico Guizini S. Oct 22, 2017 See the answer below: Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1230 views around the world You can reuse this answer Creative Commons License