Question

How do you differentiate `y= 3 / (sqrt(2x+1)`?

Answer 1

`dy/dx=-3/(2x+1)^(3/2)`

Explanation:

`y=3/sqrt(2x+1) = 3(2x+1)^(-1/2)`

`dy/dx=-3/2 (2x+1)^(-3/2) *2`

`dy/dx=-3/(2x+1)^(3/2)`