Question

How do you differentiate `y = 3 x^5 - 2e^x + 2cosx`?

Answer 1

`y' = 15x^4-2e^x-2*sin x`

Explanation:

Differentiate each term of the right side of the equation with respect to x

`y=3x^5-2e^x+2cos x`

`dy/dx=d/dx(3*x^5)-d/dx(2*e^x)+d/dx(2*cos x)`

`dy/dx=3*5x^(5-1)-2*e^x-2*sin x`

`dy/dx=15x^4-2*e^x-2*sin x`

God bless....I hope the explanation is useful.