# How do you differentiate y=3e^x-7log_10x?

Nov 29, 2017

$y ' = 3 {e}^{x} - \frac{7}{x}$

#### Explanation:

Differentiating the $e$ part:

rule: leave the ${e}^{x}$ then multiply by the differential of the power.

So it's $3 {e}^{x} \cdot 1 = 3 {e}^{x}$

Log part:

rule: function on the bottom, differential on the top

So $- 7 \cdot {\log}_{10} x$ becomes $- 7 \cdot \frac{1}{x} = - \frac{7}{x}$