Question

How do you differentiate `y = 4lnx + 2cosx - 3e^x`?

Answer 1

`f'(x) = 4/x -2sin(x) - 3e^x`

Explanation:

You simply differentiate term by term and then sum the derivatives.

`(4ln(x))' = 4*1/x; (2cos(x))' = 2*(-sin(x); (-3e^x)' = -3*e^x`.