# How do you differentiate y=(4x^2+5)(3x-5)?

Oct 11, 2015

Start by simplifying the value of $y$.

#### Explanation:

So that gives us; $12 {x}^{3} - 20 {x}^{2} + 15 x - 25$

Now for

$\frac{\mathrm{dy}}{\mathrm{dx}} = 3 \left(12\right) {x}^{2} - 2 \left(20\right) x + 15$

$= 36 {x}^{2} - 40 x + 15.$

And you end up with a quadratic equation
Classic question.