Question

How do you differentiate `y=ae^x+b/v+c/v^2`?

Answer 1

I will assume that we need to find `dy/dx` and that `a`, `b`, and `c` are constants and that `v` is some unspecified function of `x`.

Explanation:

`y=ae^x+bv^-1 + cv^-2`

`dy/dx = ae^x-bv^(-1-1) (dv)/dx -2c v^(-2-1) (dv)/dx`

`= ae^x-bv^-2 (dv)/dx -2c v^-3 (dv)/dx`

`= ae^x - b/v^2 (dv)/dx - (2c)/v^3 (dv)/dx`