How do you differentiate #y=cos(a^3+x^3)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer RedRobin9688 Jun 27, 2018 #dy/dx=-3x^2sin(a^3+x^3)# Explanation: #y=cos(a^3+x^3)# #dy/dx=-sin(a^3+x^3)*color(blue)(d/dx)(a^3+x^3)# #dy/dx=-3x^2sin(a^3+x^3)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1902 views around the world You can reuse this answer Creative Commons License