Question

How do you differentiate `y= cos(pi/2x^2-pix)` using the chain rule?

Answer 1

`-sin(pi/2x^2-pix)*(pix-pi)`

Explanation:

First, take the derivative of the outer function, cos(x): `-sin(pi/2x^2-pix)`.
But you also have to multiply this by the derivative of what's inside, (`pi/2x^2-pix`). Do this term by term.
The derivative of `pi/2x^2` is `pi/2*2x=pix`.
The derivative of `-pix` is just `-pi`.
So the answer is `-sin(pi/2x^2-pix)*(pix-pi)`