How do you differentiate # y = sin (x^2+2)# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Shaun Y. · mason m Dec 25, 2015 #y'=2x cos(x^2+2)# Explanation: To differentiate this, we have to use #D_x Sinu= cosx D_x u# So #y= sin(x^2+ 2)# #y'= cos(x^2+2)(2x)# #y'=2x cos(x^2+2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1869 views around the world You can reuse this answer Creative Commons License