How do you differentiate #y=sqrt( (x-1) (x-2) (x-3))#?
Use the chain rule!
You have two functions here:
1. the square root function
2. a factored polynomial function
If we say g(x)=(x-1)(x-2)(x-3)
then f'(x)= derivative of f with respect to g times derivative of g with respect to x, or
so the final answer is