How do you divide # (-1+5i)/(3-i) # in trigonometric form?
1 Answer
Dec 4, 2016
In Trigonometric form
Explanation:
In trigonometric form consider Z1 = (1+5i) and Z2=(3-i) and A1 = inv tan (- 5/1) = -78.69 and A2 = inv tan (- 1/3) = -18.43
the number would be
z1/z2 [cos (A1 -A2) + i sin (A1+A2)]