How do you divide (2/7)^-3(27)−3? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Alan P. Aug 1, 2015 (2/7)^(-3) = 147/8 = 18 3/8(27)−3=1478=1838 Explanation: (2/7)^-3(27)−3 color(white)("XXXX")XXXX= 1/((2/7)^3)=1(27)3 color(white)("XXXX")XXXX= 1/(2^3/7^3)=12373 color(white)("XXXX")XXXX= (7^3)/(2^3)=7323 color(white)("XXXX")XXXX= 147/8=1478 Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression (2^2/3^3)^3(2233)3? How do you simplify the expression \frac{a^5b^4}{a^3b^2}a5b4a3b2? How do you simplify ((a^3b^4)/(a^2b))^3(a3b4a2b)3 using the exponential properties? How do you simplify \frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}(3ab)2(4a3b4)3(6a2b)4? Which exponential property do you use first to simplify \frac{(2a^2bc^2)(6abc^3)}{4ab^2c}(2a2bc2)(6abc3)4ab2c? How do you simplify (x^5y^8)/(x^4y^2)x5y8x4y2? How do you simplify [(2^3 *-3^2) / (2^4 * 3^-2)]^2[23⋅−3224⋅3−2]2? See all questions in Exponential Properties Involving Quotients Impact of this question 1743 views around the world You can reuse this answer Creative Commons License