How do you divide #(2/7)^-3#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Alan P. Aug 1, 2015 #(2/7)^(-3) = 147/8 = 18 3/8# Explanation: #(2/7)^-3# #color(white)("XXXX")##= 1/((2/7)^3)# #color(white)("XXXX")##= 1/(2^3/7^3)# #color(white)("XXXX")##= (7^3)/(2^3)# #color(white)("XXXX")##= 147/8# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1519 views around the world You can reuse this answer Creative Commons License