# How do you divide  (2-7i)/(2-8i)  in trigonometric form?

Jan 19, 2016

Find the polar form ${C}_{p} = \left(R , \theta\right)$
given $C = x + i y$
Then the polar form is $R = \sqrt{{x}^{2} + {y}^{2}}$
And $\theta = {\tan}^{-} 1 \left(\frac{y}{x}\right)$

Thus R_1= sqrt(53); theta_1= tan^-1(7/2);

careful on the angle use the sign of the imaginary number to get it right (hint it is in the 4th quadrant...

R_2= sqrt(68); theta_2 = tan^-1(8/2);

again make sure you have the right angle.

now divide $R = {R}_{1} / {R}_{2}$ and the angle is simply the difference of $\theta = {\theta}_{1} - {\theta}_{2}$

Good luck, hope it helped
Yonas