Question

How do you divide `2m^2 + 3m - 14` by `2m+7`?

Answer 1

`(2m^2 +3m -14)/(2m+7) = 2m^2 – 14m + 101 - 721/(m+7)`

Explanation:

You use the process of long division.

So,

`(2m^2 + 3m -14)/(2m+7) = 2m^2 – 14m + 101 - 721/(m+7)`

Check:

`(m+7)(2m^2 – 14m + 101 + 721/(m+7)) =(m+7)( 2m^2 – 14m +101) -721= 2m^3 –cancel(14m²) +101m +cancel(14m²) -98m +707-721 = 2m^3 +3m -14`