How do you divide #(2x^3+4x^2+2x+2)/(x^2+4x-2)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Guillaume L. Jun 25, 2018 #(2x³+4x²+2x+2)/(x²+4x-2)=2x-4+(22x-6)/(x²+4x-2)# Explanation: #(2x³+4x²+2x+2)/(x²+4x-2)# #=2(x³+2x²+x+1)/(x²+4x-2)# #=2(x³+4x²-2x-2x²+3x+1)/(x²+4x-2)# #=2x(cancel((x²+4x-2)/(x²+4x-2)))^(=1)+2(-2x²+3x+1)/(x²+4x-2)# #=2x+2(-2x²-8x+4+11x-3)/(x²+4x-2)# #=2x+4(cancel((-x²-4x+2)/(x²+4x-2)))^(=-1)+(22x-6)/(x²+4x-2)# #=2x-4+(22x-6)/(x²+4x-2)# \0/ here's our answer ! Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1647 views around the world You can reuse this answer Creative Commons License