How do you divide (3x^2)/(6x - 3)?

Nov 22, 2015

${x}^{2} / \left(2 x - 1\right)$

Explanation:

You can factor in the denominator.

$6$ and $3$ both share the common factor of $3$, so we can extract $3$ from both $6$ and $3$.

$3 \left(\frac{6 x}{3} - \frac{3}{3}\right)$ $\Rightarrow$$3 \left(2 x - 1\right)$

Original equation: $\frac{3 {x}^{2}}{6 x - 3}$

New equation: $\frac{3 \left({x}^{2}\right)}{3 \left(2 x - 1\right)}$

The two $3$'s cancel out

$\frac{\cancel{3} \left({x}^{2}\right)}{\cancel{3} \left(2 x - 1\right)}$

Final equation: ${x}^{2} / \left(2 x - 1\right)$