# How do you divide #(3x^4 + 2x^3 - 11x^2 - 2x + 5)/(x^2 - 2)#?

##### 1 Answer

Use long division of the coefficients to find:

#3x^4+2x^3-11x^2-2x+5 = (x^2-2)(3x^2+2x-5) + 2x-5#

That is:

#(3x^4+2x^3-11x^2-2x+5)/(x^2-2) = 3x^2+2x-5 + (2x-5)/(x^2-2)#

#### Explanation:

Long divide the coefficients, using a long division similar to division of integers:

Note that the divisor is

Choose the first term

Multiply the divisor by

#3x^4+2x^3-11x^2-2x+5 = (x^2-2)(3x^2+2x-5) + 2x-5#