# How do you divide (-3x^4-2x^3-2x^2-2x+3)/(x^2+3) ?

Nov 11, 2017

$- 3 {x}^{2} - 2 x + 7 \frac{4 x - 18}{{x}^{2} + 3}$

#### Explanation:

One way would be to set it up as a long division:

$\textcolor{w h i t e}{\text{xxxxxxx")ul(color(white)("xx")-3x^2color(white)("x")-2xcolor(white)("xx")+7color(white)("xxxxxxxxxxxxx}}$
x^2+3" ) " -3x^4color(white)("x")-2x^3color(white)("x")-2x^2color(white)("x")-2xcolor(white)("x")+3
color(white)("xxxxxxxxx")ul(-3x^4color(white)("xxxxxxxx")-9x^2color(white)("xxxxxxxxxxx"))
$\textcolor{w h i t e}{\text{xxxxxxxxxxxxxxxx")-2x^3+7x^2color(white)("x")-2xcolor(white)("xx}} + 3$
color(white)("xxxxxxxxxxxxxxxxx")ul(-2x^3color(white)("xxxxx")-6xcolor(white)("xxxxxxx"))
$\textcolor{w h i t e}{\text{xxxxxxxxxxxxxxxxxxxxxxx")7x^2color(white)("x")+4xcolor(white)("x}} + 3$
$\textcolor{w h i t e}{\text{xxxxxxxxxxxxxxxxxxxxxxx")ul(7x^2color(white)("xxxxxx}} + 21$
$\textcolor{w h i t e}{\text{xxxxxxxxxxxxxxxxxxxxxxxxxxxxx")4xcolor(white)("x}} - 18$