How do you divide #(4x^3+3x^2+8x+12)/(3x-4) #?

1 Answer
Dec 12, 2017

#4x^3 +x^2-5#

Explanation:

So to begin, lets break down this problem to its lowest form

#(4*x^3 +3*x^2+8*x+12)/(3*x-4)=#

We can eliminate any like terms, see any? How about

#(4*x^3 +cancel(3)*x^2+8*cancel(x)+12)/(cancel(3)*cancel(x)-4)=#

Now we can get rid of #-4# by dividing it with the top

#(4*x^3 +x^2+cancel(20)^color(red)(-5))/cancel(-4)=#

So, we are left with #4x^3 +x^2-5# and that is its simplest form! There you have it! Hope this helped!
~Chandler Dowd