How do you divide #(-7-7i)/(-7-4i)#?

1 Answer
Jan 21, 2017

Answer:

For a complex number in this form, you need to multiply the numerator and denominator by the conjugate of the denominator: #-7+4i#

Explanation:

#((-7-7i)(-7+4i))/((-7-4i)(-7+4i))#
This will have the effect of eliminating the imaginary numbers in the denominator!
#(49-28i+49i-28i^2)#=#49+28+21i# = #77+21i# for the numerator.

#49-28i+28i-16i^2# = #49+16# = 65 for the denominator.
Final answer: #(77+21i)/65#.
Some textbooks require "a+bi" form: #77/65+(21i)/65#