# How do you divide (8n ^ { 3} - 48n ^ { 2} - 10) \div ( n - 6)?

$\left(8 {n}^{3} - 48 {n}^{2} + 0 n - 10\right) = 8 {n}^{2} \left(n - 6\right) \ldots . - 10$
Quotient is $8 {n}^{2}$
Remainder is $- 10$