Question

How do you divide and multiply `\frac { a + 4} { 2a ^ { 2} } \div \frac { 4} { a ^ { 2} - 5a } \cdot \frac { 2a ^ { 3} } { a ^ { 2} - 9a + 20}`?

Answer 1

`(a^2(a+4))/(4(a-4))`

Explanation:

`(a+4)/(2a^2) divide 4/(a^2-5a)*(2a^3)/(a^2-9a+20)`

`a^2-5a = a(a-5)`
`a^2-9a+20 = (a-4)(a-5)`

`(a+4)/(2a^2) divide 4/(a(a-5))*(2a^3)/((a-4)(a-5))`

`(a+4)/(2a^2) times (a(a-5))/4 times(2a^3)/((a-4)(a-5))`

Simplify.
`(a^2(a+4))/(4(a-4))`