How do you divide #\frac { 3x ( x + 4) } { 6x ( x - 2) }#?

1 Answer
Jan 25, 2018

The simplified answer is #(x+4)/(2(x-2))#

Explanation:

Cancel out the like terms #3# and #x# in the problem:

#(3x(x+4))/(6x(x-2))=>(x(x+4))/(2x(x-2))=>(x+4)/(2(x-2))#

Using the distributive property, an alternative (but equivalent) answer could be #(x+4)/(2x-4)#.