How do you divide #sqrt2/sqrt50#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Mar 30, 2015 #sqrt(50) = sqrt(2)*sqrt(25)# So #sqrt(2)/sqrt(50)# #=cancel(sqrt(2))/(cancel(sqrt(2))*sqrt(25))# #= 1/sqrt(25)# #=1/5# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1449 views around the world You can reuse this answer Creative Commons License