How do you divide #(x ^ { 2} - 7x + 6) -: ( x - 6)#?

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Answer 1 · 2018-01-05T08:12:49

#(x-1)#

#(x^2-7x+6)-:(x-6)#

Because #x^2-7x+6=(x-6)(x-1)#, we can sub that in into the original expression.

#=(x-6)(x-1)-:(x-6)#

#=(x-1)#

Answer 2 · 2018-01-05T08:15:00

#x-1#

#"factorise the numerator and simplify"#

#rArr(cancel((x-6))(x-1))/cancel((x-6))=x-1#