How do you divide #( x^3-12x^2+3x-4)/(x-2)#?

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Answer 1 · 2016-01-27T18:56:35

#x^2-10x-17-38/(x-2)#

#x^3-12x^2+3x-4 | (x-2)#

#-x^3 +2x^2 color(white)(.............)|x^2-10x-17#

#color(white)(....)-10x^2+3x-4#

#color(white)(....)+10x^2-20x #

#color(white)(................)-17x-4 #

#color(white)(................)+17x-34 #

#color(white)(...........................)-38 #

So it is:

#x^2-10x-17-38/(x-2)#