How do you divide #(x^3 + 3x^2 - 16x + 12 )/(x - 2)#?

1 Answer
Barney V. · EZ as pi
Feb 17, 2017

#(x^3+3x^2-16x+12) / (x-2) = x^2+5x-6#

Explanation:

# color(white)(..............)ulcolor(white)(........)ul(x^2+5x-6)#
#color(white)(aa)x-2##|##x^3+3x^2-16x+12#
#color(white)(..............)ul(x^3-2x^2)#
#color(white)(........................)5x^2-16x#
#color(white)(........................)ul(5x^2-10x)#
#color(white)(..............................)-6x+12#
#color(white)(...............................)ul(-6x+12)#

#(x^3+3x^2-16x+12) / (x-2) = x^2+5x-6#

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