How do you divide #(x ^ { 3} + 3x ^ { 2} + x - 1) \div ( x + 1)#?

1 Answer
Cem Sentin
Dec 7, 2017

Quotient: #x^2+2x-1# and remainder: #0#

Explanation:

#x^3+3x^2+x-1#

=#x^3+x^2+2x^2+2x-x-1#

=#x^2*(x+1)+2x*(x+1)-(x+1)#

=#(x^2+2x-1)*(x+1)#

After division #x^3+3x^2+x-1# by #x+1#, quotient is #x^2+2x-1# and remainder #0#

Related questions
Impact of this question
197 views around the world
You can reuse this answer
Creative Commons License