How do you divide #x^3+6x^2-2x+3# by x-3?

1 Answer
Tony B
Jun 27, 2017

#x^2+9x+25+78/(x-3)#

Explanation:

#" "x^3+6x^2-2x+3#
#color(magenta)(x^2)(x-3) ->ul(x^3-3x^2larr" Subtract")#
#" "0+9x^2-2x+3#
#color(magenta)(9x)(x-3)->" "ul(9x^2-27xlarr" Subtract")#
#" "0+25x+3#
#color(magenta)(25)(x-3)->" "ul(25x-75larr" Subtract")#
#" "color(magenta)(0+78 larr" Remainder")#

#color(magenta)( x^2+9x+25+78/(x-3))#

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