How do you divide #(x^3-6x^2-6x+9)div(x+1)# using synthetic division?

1 Answer
Nov 12, 2016

Answer:

The quotient is #=x^2-7x+1#
The remainder is #=8#

Explanation:

let's do the long division

#color(white)(aaaa)##x^3-6x^2-6x+9##color(white)(aa)##∣##x+1#
#color(white)(aaaa)##x^3+x^2##color(white)(aaaaaaaaaaa)##∣##x^2-7x+1#
#color(white)(aaaaa)##0-7x^2-6x#
#color(white)(aaaaaaa)##-7x^2-7x#
#color(white)(aaaaaaaaaaa)##0+x+9#
#color(white)(aaaaaaaaaaaaa)##+x+1#
#color(white)(aaaaaaaaaaaaa)##+0+8#

So the quotient is #=x^2-7x+1#

and the remainder #=8#