# How do you divide #(x^4-2x^3-2x^2-2x+3)/(x^2-3) #?

##### 1 Answer

Dec 6, 2015

Long divide the coefficients to find:

#(x^4-2x^3-2x^2-2x+3)/(x^2-3) = x^2-2x+1+(-8x+6)/(x^2-3)#

#### Explanation:

I like to long divide the coefficients like this:

Note that the divisor is written

Write the *dividend* under the bar and the *divisor* to the left.

Write the *quotient* term-by-term above the bar, choosing each digit so that when multiplied by the divisor it matches the leading term of your running remainder. Once the remainder is too short to allow further division, you are finished.

The quotient represented by