# How do you divide #(-x^4-3x^3-2x^2-4x-7)/(x^2+3) #?

##### 2 Answers

The result is

#### Explanation:

Looking at the orders of the numerator and the denominator, we can see the result should be of order 2.

We can deduce the first term will be

Looking at the constants in the numerator it seems there must be a remainder, since 3 is not a factor of 7.

We write the numerator as a product of two quadratics (the known denominator and the unknown quotient) plus a linear term (the unknown remainder):

Comparing coefficients of

Comparing coefficients of

Comparing coefficients of

Comparing constants, we see that:

Hence the result is

#### Explanation:

Note that I use place keepers such as

Putting all this together we have: