How do you draw the line with the x intercept of -4 and y intercept of -1/2?

1 Answer
Sep 13, 2017

Answer:

See a solution process below

Explanation:

The #x#-intercept is the point on the #x#-axis where the line crosses. Therefore, the #x# value is #0#. So, we can write the #x#-intercept of #-4# as: #(0, -4)#

Likewise, the #y#-intercept is the point on the #y#-axis where the line crosses. Therefore, the #y# value is #0#. So, we can write the #y#-intercept of #-1/2# as: #(-1/2, 0)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y+4)^2-0.05)((x-0.5)^2+y^2-0.05)=0 [-15, 15, -7.5, 7.5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x^2+(y+4)^2-0.05)((x-0.5)^2+y^2-0.05)(-8x+y+4)=0 [-15, 15, -7.5, 7.5]}