# How do you draw the line with the x intercept of -4 and y intercept of -1/2?

Sep 13, 2017

See a solution process below

#### Explanation:

The $x$-intercept is the point on the $x$-axis where the line crosses. Therefore, the $x$ value is $0$. So, we can write the $x$-intercept of $- 4$ as: $\left(0 , - 4\right)$

Likewise, the $y$-intercept is the point on the $y$-axis where the line crosses. Therefore, the $y$ value is $0$. So, we can write the $y$-intercept of $- \frac{1}{2}$ as: $\left(- \frac{1}{2} , 0\right)$

We can next graph the two points on the coordinate plane:

graph{(x^2+(y+4)^2-0.05)((x-0.5)^2+y^2-0.05)=0 [-15, 15, -7.5, 7.5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x^2+(y+4)^2-0.05)((x-0.5)^2+y^2-0.05)(-8x+y+4)=0 [-15, 15, -7.5, 7.5]}